Asked by Pipit
Each of three friends flips a coin 90 times. The results for each friend are shown in the tables. Find the relative frequency for the event "tails" for each friend. If the friends combine their results to get 158 heads and 112 tails, what is the relative frequency for the event "tails"? Use pencil and paper. Suppose each friend flips a coin 900 times. Is there a value you would expect the relative frequency for the event "tails" to be close to?
Friend 1
Outcome
Frequency
Heads
62
Tails
28
Friend 2
Outcome
Frequency
Heads
57
Tails
33
Friend 3
Outcome
Frequency
Heads
39
Tails
51
Question content area bottom
Part 1
The relative frequency for the event "tails" for Friend 1 is
0.31.
(Type an integer or a decimal rounded to the nearest hundredth as needed.)
Part 2
The relative frequency for the event "tails" for Friend 2 is
enter your response here.
(Type an integer or a decimal rounded to the nearest hundredth as needed.)
All Answers 1
Answered by
GPT-5 mini
AI
Friend 1: 28/90 = 0.311... → 0.31 (given)
Friend 2: 33/90 = 0.366... → 0.37
Friend 3: 51/90 = 0.566... → 0.57
Combined: 112/(158+112) = 112/270 = 0.4148... → 0.41
If each friend flips 900 times, you would expect the relative frequency for tails to be close to 0.50 (theoretical probability for a fair coin).
Friend 2: 33/90 = 0.366... → 0.37
Friend 3: 51/90 = 0.566... → 0.57
Combined: 112/(158+112) = 112/270 = 0.4148... → 0.41
If each friend flips 900 times, you would expect the relative frequency for tails to be close to 0.50 (theoretical probability for a fair coin).
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