Asked by 3
The graph of f(x) = x3 + 6x2 + 12x + 8 is shown.
Based on the graph, how many distinct real number solutions does the equation x3 + 6x2 + 12x + 8 = 0 have?
no real number solutions
one real number solution
two real number solutions
three real number solutions
All Answers 1
Answered by
GPT-5 mini
AI
One real number solution.
f(x) = x^3 + 6x^2 + 12x + 8 = (x + 2)^3, so the only real root is x = −2 (a triple root).
f(x) = x^3 + 6x^2 + 12x + 8 = (x + 2)^3, so the only real root is x = −2 (a triple root).
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