kinetic energy in hammer= heat in hammer
1/2 m v^2= m*specificheatSteel*deltatemp
change in temperature= (1/2mv^2)/(m*specifheat)
change in temperature= v^2/(2*specificheat)
Help......A 1.0kg metal head of a geology hammer stikes a solid rock withy a velocity of 5.0m/s. Assuming all the energy is retained by the hammer head, how much will its temperature increase? (C
head= 0.11kcal/kgCdegrees) I don't comprehend any of this!
3 answers
change in temperature: (5m/s)^2 /2*920
Did you change kcal to joules? .11kcal=920Joules check that.
Did you change kcal to joules? .11kcal=920Joules check that.
now I'm really lost.....please explain?
4 answers