Asked by j
Find the horizontal asymptote of the function .
y =
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Answered by
GPT-5 mini
AI
It looks like the formula didn’t come through — could you paste the full function y = ?
Meanwhile, here are quick rules you can use to find horizontal asymptotes (HA):
1. Definition (general): y = L is a horizontal asymptote if lim_{x→∞} f(x) = L or lim_{x→−∞} f(x) = L. You should check both ±∞ (they can be different).
2. For rational functions f(x) = P(x)/Q(x) (polynomials):
- deg(P) < deg(Q) → HA: y = 0.
- deg(P) = deg(Q) → HA: y = (leading coefficient of P) / (leading coefficient of Q).
- deg(P) = deg(Q) + 1 → no horizontal asymptote; there may be a slant (oblique) asymptote found by polynomial long division.
- deg(P) > deg(Q) + 1 → no horizontal asymptote (end behavior grows without approaching a constant).
3. Other common cases:
- Exponentials: e^{−x} → HA y = 0 as x→∞; e^{x} has no HA as x→∞.
- Inverse trig: arctan x → HA y = ±π/2 as x→±∞.
- Use limits if unsure.
Examples:
- y = (3x^2 + 5)/(2x^2 − 1) → deg equal → HA y = 3/2.
- y = (2x + 1)/(x^2 + 1) → deg numerator < denominator → HA y = 0.
- y = (x^3)/(x^2 + 1) → deg numerator > denominator by 1 → no horizontal asymptote (slant asymptote instead).
If you post the exact function, I’ll compute the horizontal asymptote(s) for you.
Meanwhile, here are quick rules you can use to find horizontal asymptotes (HA):
1. Definition (general): y = L is a horizontal asymptote if lim_{x→∞} f(x) = L or lim_{x→−∞} f(x) = L. You should check both ±∞ (they can be different).
2. For rational functions f(x) = P(x)/Q(x) (polynomials):
- deg(P) < deg(Q) → HA: y = 0.
- deg(P) = deg(Q) → HA: y = (leading coefficient of P) / (leading coefficient of Q).
- deg(P) = deg(Q) + 1 → no horizontal asymptote; there may be a slant (oblique) asymptote found by polynomial long division.
- deg(P) > deg(Q) + 1 → no horizontal asymptote (end behavior grows without approaching a constant).
3. Other common cases:
- Exponentials: e^{−x} → HA y = 0 as x→∞; e^{x} has no HA as x→∞.
- Inverse trig: arctan x → HA y = ±π/2 as x→±∞.
- Use limits if unsure.
Examples:
- y = (3x^2 + 5)/(2x^2 − 1) → deg equal → HA y = 3/2.
- y = (2x + 1)/(x^2 + 1) → deg numerator < denominator → HA y = 0.
- y = (x^3)/(x^2 + 1) → deg numerator > denominator by 1 → no horizontal asymptote (slant asymptote instead).
If you post the exact function, I’ll compute the horizontal asymptote(s) for you.
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