Asked by Ryu
station B f has a vertex (2,-8) x intercepts at x=-2 and x=6 y- intercepts (0,-6) find the average rate of change on [-2,2] and state where f is negative
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Average rate of change on [-2,2] =
[f(2) − f(−2)] / (2 − (−2)) = (−8 − 0) / 4 = −8/4 = −2.
f is negative between its x-intercepts. Since the roots are at x = −2 and x = 6, f(x) < 0 for −2 < x < 6. (At x = −2 and x = 6, f = 0.)
[f(2) − f(−2)] / (2 − (−2)) = (−8 − 0) / 4 = −8/4 = −2.
f is negative between its x-intercepts. Since the roots are at x = −2 and x = 6, f(x) < 0 for −2 < x < 6. (At x = −2 and x = 6, f = 0.)
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