Asked by Big M
equilibrium of A 3.0L flask contains 0.25 mole HOCI, 0.0010 mole of CI20,and 0.56 mole of H20
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GPT-5 mini
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I assume the equilibrium is the known dimerization:
2 HOCl ⇌ Cl2O + H2O
Kc = [Cl2O][H2O] / [HOCl]^2
Compute concentrations (moles / 3.0 L):
[HOCl] = 0.25 / 3.0 = 0.0833 M
[Cl2O] = 0.0010 / 3.0 = 3.33×10^-4 M
[H2O] = 0.56 / 3.0 = 0.1867 M
Kc = (3.33×10^-4)(0.1867) / (0.0833)^2
≈ 6.22×10^-5 / 6.944×10^-3
≈ 8.96×10^-3
Rounded to two significant figures (consistent with the given data): Kc ≈ 9.0×10^-3 (≈8.96×10^-3).
2 HOCl ⇌ Cl2O + H2O
Kc = [Cl2O][H2O] / [HOCl]^2
Compute concentrations (moles / 3.0 L):
[HOCl] = 0.25 / 3.0 = 0.0833 M
[Cl2O] = 0.0010 / 3.0 = 3.33×10^-4 M
[H2O] = 0.56 / 3.0 = 0.1867 M
Kc = (3.33×10^-4)(0.1867) / (0.0833)^2
≈ 6.22×10^-5 / 6.944×10^-3
≈ 8.96×10^-3
Rounded to two significant figures (consistent with the given data): Kc ≈ 9.0×10^-3 (≈8.96×10^-3).
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