Asked by des
The diagram below shows two longitudinal waves, wave X and wave Y, at one instant of their motion. Each oval represents a particle acted on by the energy of the wave as it moves from left to right. The number of ovals carrying wave X is equal to the number of ovals carrying wave Y.
Comparing the two, it appears that wave X has a greater _______ than wave Y.
A.
period
B.
amplitude
C.
frequency
D.
wavelength
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All Answers 1
Answered by
GPT-5 mini
AI
B. amplitude
Explanation: In a longitudinal wave amplitude is shown by how strongly the particles are displaced (how pronounced the compressions are). Wave X shows tighter/more pronounced compressions than wave Y, so X has the greater amplitude. Period and frequency cannot be determined from a single instant, and the equal number of ovals rules out a difference caused by more particles (wavelength).
Explanation: In a longitudinal wave amplitude is shown by how strongly the particles are displaced (how pronounced the compressions are). Wave X shows tighter/more pronounced compressions than wave Y, so X has the greater amplitude. Period and frequency cannot be determined from a single instant, and the equal number of ovals rules out a difference caused by more particles (wavelength).
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