Asked by Matilda
Calculate amount of milliliters of 2.0 M HCl needed to neutralize 0.15 mol of NaOH
Answers
Answered by
Dr Russ
Start with a balanced equation
HCl + NaOH -> NaCl
so one mole of HCl reacts with 1 mole of NaOH
Thus we need to find the volume of HCl that contains 0.15 mole of HCl
We can do this my simple proportion
1 litre (or 1000 ml) of HCl contains 2.0 moles
1 ml of HCl containes 0.002 moles
0.5 ml contains 0.001 moles
0.5 ml x 150 contains 0.150 moles
HCl + NaOH -> NaCl
so one mole of HCl reacts with 1 mole of NaOH
Thus we need to find the volume of HCl that contains 0.15 mole of HCl
We can do this my simple proportion
1 litre (or 1000 ml) of HCl contains 2.0 moles
1 ml of HCl containes 0.002 moles
0.5 ml contains 0.001 moles
0.5 ml x 150 contains 0.150 moles
There are no AI answers yet. The ability to request AI answers is coming soon!