Question

Solve the system of two equations using elimination with multiplication.
4x−6y=−48
4
𝑥
−
6
𝑦
=
−
48

−2x+4y=30

Answer 1

Solve the system
4x − 6y = −48
−2x + 4y = 30

Multiply the second equation by 2 to eliminate x when added:
2(−2x + 4y) = 2(30) → −4x + 8y = 60

Add this to the first equation:
(4x − 6y) + (−4x + 8y) = −48 + 60
2y = 12 → y = 6

Substitute y = 6 into 4x − 6y = −48:
4x − 6(6) = −48 → 4x − 36 = −48 → 4x = −12 → x = −3

Solution: x = −3, y = 6 (check: −2(−3) + 4(6) = 6 + 24 = 30).