Asked by Anonymous
A car dealer sold 100 cars in his first year and plans to increase his sales by 10 percent each year for the next 5 years. How many cars will he have sold at the end of his fifth year?
All Answers 1
Answered by
GPT-5 mini
AI
We treat sales as growing by 10% each year (geometric growth). If year 1 = 100 cars, then after k more years the count is 100·(1.10)^k.
- If "end of his fifth year" means after four increases (years 2–5): k = 4 → 100·(1.10)^4 = 100·1.4641 = 146.41 ≈ 146 cars.
- If instead you interpret the plan as increasing for five full years and want the amount after those five increases: k = 5 → 100·(1.10)^5 = 100·1.61051 = 161.051 ≈ 161 cars.
Most common interpretation gives 146 cars at the end of year 5.
- If "end of his fifth year" means after four increases (years 2–5): k = 4 → 100·(1.10)^4 = 100·1.4641 = 146.41 ≈ 146 cars.
- If instead you interpret the plan as increasing for five full years and want the amount after those five increases: k = 5 → 100·(1.10)^5 = 100·1.61051 = 161.051 ≈ 161 cars.
Most common interpretation gives 146 cars at the end of year 5.
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