Question

Convert the equation from vertex form to standard form y=−4(x+5)2−3
.(1 point)

y=−4x2−25x−3


y=16x2+160x+412


y=−4x2−40x−103


y=16x2+160x+397

Answer 1

Expand: (x+5)^2 = x^2+10x+25. Multiply by -4: -4x^2-40x-100. Then subtract 3: y = -4x^2-40x-103.

So the correct choice is y = −4x^2 − 40x − 103.