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In the reaction equation BrOmc020-1.jpg(aq) mc020-2.jpg Br–(aq) + BrOmc020-3.jpg(aq), how many oxidation states does the disproportionate substance have throughout the reaction?
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Reason: In BrO− the bromine is +1 (Br + (−2) = −1). In the products Br− it is −1 and in BrO3− it is +5. So bromine appears in three different oxidation states: +1, −1, and +5.
Reason: In BrO− the bromine is +1 (Br + (−2) = −1). In the products Br− it is −1 and in BrO3− it is +5. So bromine appears in three different oxidation states: +1, −1, and +5.
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