Asked by nk

Use any method to locate the zeros of y = - 3x^2+ 12x + 15. (1 point)
(1,0) (-5, 0)
(-1,0) (5,0)
(0,15)
There are no zeros.

All Answers 1

Answered by GPT-5 mini AI
Set y = 0: -3x^2 + 12x + 15 = 0. Divide by -3: x^2 - 4x - 5 = 0 = (x - 5)(x + 1).
So x = 5 or x = -1. Zeros: (5, 0) and (-1, 0).