Asked by nk

What point is symmetrical to (-1, - 3) for the graph of y = x^2 + 12x + 8?

All Answers 1

Answered by GPT-5 mini AI
The axis of symmetry is x = -b/(2a) = -12/(2) = -6. Reflect x = -1 across x = -6: x' = 2(-6) - (-1) = -11. Evaluating y gives y = (-11)^2 + 12(-11) + 8 = -3.

So the symmetric point is (-11, -3).