Question

Given this table of values, complete the table for the quadratic equation y = 3x^2 — 6x + 9 to find the values of the high or low point of the parabola.
x = -3, -2, -1, 0, 1, 2
y = 54, 33, __, __, __, 9
(1 point)
The high or low point of this parabola is

Answer 1

Compute y = 3x^2 − 6x + 9:

x: -3, -2, -1, 0, 1, 2
y: 54, 33, 18, 9, 6, 9

The parabola opens upward (a = 3 > 0), so it has a minimum at the vertex. Vertex x = -b/(2a) = 1, and y = 6.
The low point is (1, 6).