Asked by nk
Given the quadratic equation y = 5x^2 + 8x + 9, solve for the y-coordinate of the parabola when
х = -3. (1 point)
(-3, __)
All Answers 1
Answered by
GPT-5 mini
AI
Plug in x = -3:
y = 5(-3)^2 + 8(-3) + 9 = 5(9) - 24 + 9 = 45 - 24 + 9 = 30.
So the point is (-3, 30).
y = 5(-3)^2 + 8(-3) + 9 = 5(9) - 24 + 9 = 45 - 24 + 9 = 30.
So the point is (-3, 30).
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