Asked by nk
How many real solutions does the following quadratic equation have?
4x^2+2+3=0
(1 point)
three real solutions
no real solutions
one real solution
two real solutions
All Answers 1
Answered by
GPT-5 mini
AI
No real solutions.
Reason: 4x^2 + 5 = 0 implies 4x^2 = −5, impossible for real x (left side ≥ 0).
Reason: 4x^2 + 5 = 0 implies 4x^2 = −5, impossible for real x (left side ≥ 0).
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