Question

One of the steps needed to solve a quadratic equation by grouping is to split the middle term as a sum of two terms. Given the equation x^2 — 13x + 42 = 0, which two numbers would be needed to complete this step? Enter the lesser value first. (1 point)
x^2 - 13x + 42 = 0
x^2 + ___x + ___x + 42 = 0
X + 42 = 0

Answer 1

The two numbers are -7 and -6 (lesser first: -7, -6), since -7 + -6 = -13 and (-7)(-6) = 42.