Question

Suppose you were to graph a parabola given by the equation y=14x2+3x−1
. Which ordered pair would be the vertex of the graph?(1 point)

(−6,−10)


(−6,−1)


(−6,−9)


(−6,−11)

Answer 1

Interpreting "14x2" as (1/4)x^2, a = 1/4 and b = 3. Vertex x = -b/(2a) = -3/(2·1/4) = -3/(1/2) = -6.
y = (1/4)(-6)^2 + 3(-6) - 1 = 9 - 18 - 1 = -10.

So the vertex is (-6, -10).