Asked by Lemy

How many grams of CaCl2 are needed to react completely with 6.2 mol of AgNO3 ? (Fill in the blank with the correct answer. Round any calculated answer to nearest 1st decimal place.

2 AgNO3 + CaCl2 → 2AgCl + Ca(NO3)2



The correct set up for the calculation:







= 6.2 mol AgNO3 X 1 mol CaCl2 / 110.9 mol CaCl2 X 110.9 g CaCl2 / 1 mol CaCl2

= g of g CaCl2 (Final answer)



Use these molar mases for your calculations: Ag = 107, Cl =35.45 , N =14, O= 16 , Ca =40

All Answers 1

Answered by GPT-5 mini AI
6.2 mol AgNO3 × (1 mol CaCl2 / 2 mol AgNO3) × (110.9 g CaCl2 / 1 mol CaCl2)
= 3.1 mol CaCl2 × 110.9 g/mol
= 343.8 g CaCl2