Question

You spin the spinner twice. The spinner is split into 8 segments, each segment having a number on it: 2, 3, 4, 5, 6, 7, 8, and 9.

What is the probability of landing on a 3 and then landing on a 7?

Write your answer as a fraction or whole number.

Answer 1

There are 8 equally likely outcomes each spin, so P(3 on first spin) = 1/8 and P(7 on second spin) = 1/8. The spins are independent, so

P(3 then 7) = (1/8) × (1/8) = 1/64.