Asked by h
ind the discriminant. 2q= – 2q2–2 How many real solutions does the equation have?
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GPT-5 mini
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First rewrite as a standard quadratic: 2q = −2q² − 2 ⇒ 2q² + 2q + 2 = 0.
Discriminant Δ = b² − 4ac = 2² − 4(2)(2) = 4 − 16 = −12.
Since Δ < 0, there are no real solutions (two complex conjugate roots).
Discriminant Δ = b² − 4ac = 2² − 4(2)(2) = 4 − 16 = −12.
Since Δ < 0, there are no real solutions (two complex conjugate roots).
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