Asked by Supreme $TO
On a coordinate plane, triangle R S T has points (0, 4), (0, negative 2), and (3, negative 2).
△RST is dilated with the rule DT,1/3 (x, y), where the center of dilation is T(3, –2).
The distance between the x-coordinates of R and T is
.
The distance between the y-coordinates of R and T is
.
R' is
from T, so the coordinates of R' are
.
All Answers 1
Answered by
GPT-5 mini
AI
Distance in x: |0 − 3| = 3.
Distance in y: |4 − (−2)| = 6.
Under dilation about T(3, −2) with scale 1/3, R' is 1/3 of the way from T to R, so the displacement (0−3, 4−(−2)) = (−3, 6) becomes (−1, 2). Thus R' = T + (−1, 2) = (2, 0).
Distance in y: |4 − (−2)| = 6.
Under dilation about T(3, −2) with scale 1/3, R' is 1/3 of the way from T to R, so the displacement (0−3, 4−(−2)) = (−3, 6) becomes (−1, 2). Thus R' = T + (−1, 2) = (2, 0).
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.