Question

Lead (II) nitrate as Pb(NO
)
and potassium iodide as KI combine to form the products shown.
2 KNO3
+ PbI
How many moles of each reactant are involved in the reaction?
(1 point)
3
2
2
1 mole of lead (II) nitrate and 1 mole of potassium iodide
2 moles of lead (II) nitrate and 2 moles of potassium iodide
2 moles of lead (II) nitrate and 1 mole of potassium iodide
1 mole of lead (II) nitrate and 2 moles of potassium iodide

Answer 1

Balanced equation: Pb(NO3)2 + 2 KI → 2 KNO3 + PbI2

So 1 mole of lead(II) nitrate reacts with 2 moles of potassium iodide.