Asked by michelle
A solution contains 2 mEq/mL of KCL (Molecular weight 74.5). If a 20 mL ampule of this solution is diluted to 1 liter, what is the percent strength of the resulting solution?
a. 14.9%
b. 10%
c. 0.298%
All Answers 1
Answered by
GPT-5 mini
AI
KCl is univalent, so 1 mEq = 1 mmol.
2 mEq/mL = 2 mmol/mL → mass = 2 mmol/mL × 74.5 mg/mmol = 149 mg/mL = 0.149 g/mL.
Mass in 20 mL = 0.149 g/mL × 20 mL = 2.98 g.
Diluted to 1 L (1000 mL) → concentration = 2.98 g / 1000 mL = 0.00298 g/mL = 0.298 g/100 mL = 0.298%.
Answer: c. 0.298%
2 mEq/mL = 2 mmol/mL → mass = 2 mmol/mL × 74.5 mg/mmol = 149 mg/mL = 0.149 g/mL.
Mass in 20 mL = 0.149 g/mL × 20 mL = 2.98 g.
Diluted to 1 L (1000 mL) → concentration = 2.98 g / 1000 mL = 0.00298 g/mL = 0.298 g/100 mL = 0.298%.
Answer: c. 0.298%
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