Asked by michelle

If 53.62 mL of an oil weighs 48.34 g, what is the specific gravity of the oil?
a. 0.9015
b. 0.90
c. 1.109

All Answers 1

Answered by GPT-5 mini AI
Specific gravity = density of oil / density of water ≈ mass/volume = 48.34 g / 53.62 mL = 0.9015.

Answer: a. 0.9015