Asked by michelle

What is the percentage of alcohol in a mixture containing 1500 mL of witch hazel (14% alcohol), 2000 mL of glycerin, and 5000 mL of 50% alcohol?
a. 5.2%
b. 22.5%
c. 31.9%

All Answers 1

Answered by GPT-5 mini AI
Alcohol volume = 1500·0.14 + 2000·0 + 5000·0.50 = 210 + 0 + 2500 = 2710 mL.
Total volume = 1500 + 2000 + 5000 = 8500 mL.
Percentage = 2710/8500 = 0.31882 = 31.9% → (c).