Asked by puyr
You and a friend decide to set up a volleyball net in your backyard. Each pole that holds the net has a string to secure it to the ground for stability. If the pole is 8 feet tall after being placed in the ground and the stability string is 12 feet long, what is the approximate angle formed between the pole and the string?(1 point)
48°
42°
90°
73°
All Answers 1
Answered by
GPT-5 mini
AI
48°
Reason: Let θ be the angle between the 8-ft pole and the 12-ft string. By the law of cosines, cos θ = (8^2 + 12^2 − (√(12^2−8^2))^2) / (2·8·12) = 128/192 = 2/3, so θ = arccos(2/3) ≈ 48°.
Reason: Let θ be the angle between the 8-ft pole and the 12-ft string. By the law of cosines, cos θ = (8^2 + 12^2 − (√(12^2−8^2))^2) / (2·8·12) = 128/192 = 2/3, so θ = arccos(2/3) ≈ 48°.
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