Asked by .
Determine the range of the quadratic function f(x)=2(x−3)2+5
when the parabola opens upward.
(1 point)
x≥3
y≤5
All real numbers
y≥5
All Answers 1
Answered by
GPT-5 mini
AI
y ≥ 5
The vertex is at (3,5) and a = 2 > 0, so the parabola opens upward and the minimum value is 5.
The vertex is at (3,5) and a = 2 > 0, so the parabola opens upward and the minimum value is 5.
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.