Question

What is the molar mass of Carbon ?

a
24 g/mol
b
12 g
c
12 g/mol
d
24 g
Question 2 (1 point)
What is the mass of 1 mol of Carbon ?

a
24 g
b
12 g/ mol
c
1 g/ mol
d
12 g
e
24 g/mol
f
1 g
Question 3 (4 points)
3.0095 x 1011 in normal notation is:

a
30950000000
b
0.000000000030095
c
0.0000000030095
d
300950000000
Question 4 (4 points)
3.095 x 10-11 in normal notation is:

a
30950000000
b
300950000000
c
0.00000000003095
d
0.000000000030095
Question 5 (10 points)
How many moles of C atoms are found in the quantities given below?

A) 6.022 x1023 of C atoms _ mol

B) 6.022 x1025 of C atoms _ mol

C) 3.011 x1023 of C atoms _ mol

D) 3.011 x1024 of C atoms _ mol

E) 3.011 x1025 of C atoms _ mol

Column A
1.
A:
A
2.
B:
B
3.
C:
C
4.
D:
D
5.
E:
E
Column B
a.5 mol C atoms
b.1 mol C atoms
c.100 mol C atoms
d.0.5 mol C atoms
e.50 mol C atoms
Question 6 (10 points)
Molar masses of elements: H = 1, C =12, N =14, O=16, F =19, Na =23, Mg=24, Al=27, P=31, S=32, Cl=35.5, Ca=40, Fe=56, Cu=63.5, Ba=137



Calculate the molar mass of Fe2(SO4)3 using the molar masses of elements given above. g/mol. (Round to nearest first decimal place if you get a decimal value)

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Question 7 (10 points)
Molar masses of elements: H = 1, C =12, N =14, O=16, F =19, Na =23, Mg=24, Al=27, P=31, S=32, Cl=35.5, Ca=40, Fe=56, Cu=63.5, Ba=137



Calculate the molar mass of Ba3(PO4)2 using the molar masses of elements given above. g/mol (Round to nearest first decimal place if you get a decimal value)

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Question 8 (10 points)
Molar masses of elements: H = 1, C =12, N =14, O=16, F =19, Na =23, Mg=24, Al=27, P=31, S=32, Cl=35.5, Ca=40, Fe=56, Cu=63.5, Ba=137



Calculate the molar mass of Al2(CO3)3 using the molar masses of elements given above. g/mol. (Round to nearest first decimal place if you get a decimal value)

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Answer 1

Here are the answers:

Question 1
- Correct: c) 12 g/mol

Question 2
- Correct: d) 12 g

Question 3
- Correct: d) 300950000000

Question 4
- Correct: c) 0.00000000003095

Question 5 (moles)
A) 6.022×10^23 atoms → 1 mol (option b)
B) 6.022×10^25 atoms → 100 mol (option c)
C) 3.011×10^23 atoms → 0.5 mol (option d)
D) 3.011×10^24 atoms → 5 mol (option a)
E) 3.011×10^25 atoms → 50 mol (option e)

Question 6
- Fe2(SO4)3 = 2(56) + 3[32 + 4(16)] = 400 g/mol

Question 7
- Ba3(PO4)2 = 3(137) + 2[31 + 4(16)] = 601 g/mol

Question 8
- Al2(CO3)3 = 2(27) + 3[12 + 3(16)] = 234 g/mol