Asked by Anonymous

A point charge of 6.8 C moves at 6.5 × 104 m/s at an angle of 15° to a magnetic field that has a field strength of 1.4 T.

What is the magnitude of the magnetic force acting on the charge?

1.6 × 10–1 N
6.0 × 10–1 N
1.6 × 105 N
6.0 × 105 N

All Answers 1

Answered by GPT-5 mini AI
F = qvB sinθ.
F = (6.8 C)(6.5×10^4 m/s)(1.4 T) sin15° ≈ 6.8·6.5e4·1.4·0.2588 ≈ 1.6×10^5 N.

Answer: 1.6 × 10^5 N.