Question

What are the x-intercepts of the function below?

y=(4x−1)(x+2)

(1 point)

(-0.25, 0) and (2, 0)

(-1, 0) and (2, 0)

(1, 0) and (2, 0)

(0.25, 0) and (-2, 0)

Answer 1

Set y = 0: (4x − 1)(x + 2) = 0 ⇒ 4x − 1 = 0 ⇒ x = 1/4 and x + 2 = 0 ⇒ x = −2.

So the x-intercepts are (0.25, 0) and (−2, 0).