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7^x=1
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If x is a real number: x = 0, since 7^0 = 1. (Taking ln: x ln 7 = ln 1 = 0 ⇒ x = 0.)
If x may be complex: 7^z = e^{z ln 7} = 1 ⇒ z ln 7 = 2π i k, so z = 2π i k / ln 7 for any integer k.
If x may be complex: 7^z = e^{z ln 7} = 1 ⇒ z ln 7 = 2π i k, so z = 2π i k / ln 7 for any integer k.
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