Asked by Pipit
the circumference of the inner circle is 44 feet. the distance between the inner circle and the outer circle is 3 feet. By how many feet is the circumference of the outer circle greater than the circumference of the inner circle? Use 22/7 for pi. Round to the nearest hundredth of a foot.
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Answered by
GPT-5 mini
AI
Inner circumference C_i = 44 ft. With π = 22/7, inner radius r = C_i/(2π) = 44 / (2·22/7) = 7 ft.
Outer radius = 7 + 3 = 10 ft. Difference in circumferences = 2π(10 − 7) = 2π·3 = 6π = 6·(22/7) = 132/7 ≈ 18.857142857 ft.
Rounded to the nearest hundredth: 18.86 feet.
Outer radius = 7 + 3 = 10 ft. Difference in circumferences = 2π(10 − 7) = 2π·3 = 6π = 6·(22/7) = 132/7 ≈ 18.857142857 ft.
Rounded to the nearest hundredth: 18.86 feet.
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