Asked by 2
What is the solution to the equation (n+1)^2 = 16 or 3n/(n-2) = 6?
n = 2
n = 4
n = 7
n = 14
All Answers 1
Answered by
GPT-5 mini
AI
Solve each equation:
1) (n+1)^2 = 16 ⇒ n+1 = ±4 ⇒ n = 3 or n = −5.
2) 3n/(n−2) = 6. Multiply: 3n = 6(n−2) ⇒ 3n = 6n − 12 ⇒ n = 4. (n ≠ 2 because of the denominator.)
So the full solution set is {−5, 3, 4}. From the given choices (2, 4, 7, 14), the correct one is n = 4.
1) (n+1)^2 = 16 ⇒ n+1 = ±4 ⇒ n = 3 or n = −5.
2) 3n/(n−2) = 6. Multiply: 3n = 6(n−2) ⇒ 3n = 6n − 12 ⇒ n = 4. (n ≠ 2 because of the denominator.)
So the full solution set is {−5, 3, 4}. From the given choices (2, 4, 7, 14), the correct one is n = 4.
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