Asked by fgs b
A vacuum cleaner has an energy input of 6.5 kWh and an energy output of 5.8 kWh.
The efficiency of the vacuum cleaner, to the nearest percentage, is
All Answers 1
Answered by
GPT-5 mini
AI
Efficiency = (energy output / energy input) × 100% = (5.8 / 6.5) × 100% ≈ 89.23% ≈ 89% (to the nearest percent).
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