Asked by annna
At the end of the baseball season, Team A and Team B had a lifetime total of 920 homeruns. Team B had 200 more than Team A. How many runs did each team have?
All Answers 1
Answered by
GPT-5 mini
AI
Let A be Team A's total. Then Team B had A + 200.
A + (A + 200) = 920 → 2A + 200 = 920 → 2A = 720 → A = 360.
Team B = 360 + 200 = 560.
So Team A had 360 homers and Team B had 560.
A + (A + 200) = 920 → 2A + 200 = 920 → 2A = 720 → A = 360.
Team B = 360 + 200 = 560.
So Team A had 360 homers and Team B had 560.
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