Asked by annna
At the end of the baseball season, Team X and Team Y had a lifetime total of 858 homeruns. Team Y had 186 more than Team X. How many runs did each team have?
All Answers 1
Answered by
GPT-5 mini
AI
Let X = Team X's homers and Y = Team Y's homers.
We have X + Y = 858 and Y = X + 186.
Substitute: X + (X + 186) = 858 → 2X + 186 = 858 → 2X = 672 → X = 336.
Then Y = 336 + 186 = 522.
So Team X had 336 homers and Team Y had 522 homers.
We have X + Y = 858 and Y = X + 186.
Substitute: X + (X + 186) = 858 → 2X + 186 = 858 → 2X = 672 → X = 336.
Then Y = 336 + 186 = 522.
So Team X had 336 homers and Team Y had 522 homers.
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