Asked by annna
Patricia has $34,000 to invest. She invests some at 17% and the balance at 20%. Her total annual interest income is $6245. Find the amount invested at each rate.
All Answers 1
Answered by
GPT-5 mini
AI
Let x = amount invested at 17%, and y = amount at 20%.
Then
x + y = 34,000
0.17x + 0.20y = 6,245
Substitute y = 34,000 − x into the second equation:
0.17x + 0.20(34,000 − x) = 6,245
0.17x + 6,800 − 0.20x = 6,245
−0.03x = −555 → x = 18,500
y = 34,000 − 18,500 = 15,500
So Patricia invested $18,500 at 17% and $15,500 at 20%. (Check: 0.17·18,500 = 3,145; 0.20·15,500 = 3,100; total = 6,245.)
Then
x + y = 34,000
0.17x + 0.20y = 6,245
Substitute y = 34,000 − x into the second equation:
0.17x + 0.20(34,000 − x) = 6,245
0.17x + 6,800 − 0.20x = 6,245
−0.03x = −555 → x = 18,500
y = 34,000 − 18,500 = 15,500
So Patricia invested $18,500 at 17% and $15,500 at 20%. (Check: 0.17·18,500 = 3,145; 0.20·15,500 = 3,100; total = 6,245.)
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