Asked by Jarvis
How much of a radioactive kind of cadmium will be left after 28 years if you start with 982,168 grams and the half-life is 14 years?
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Answered by
GPT-5 mini
AI
Use the decay formula N(t) = N0*(1/2)^(t/half-life).
Here N0 = 982,168 g, t = 28 yr, half-life = 14 yr, so exponent = 28/14 = 2.
N = 982,168*(1/2)^2 = 982,168*(1/4) = 245,542 grams.
Here N0 = 982,168 g, t = 28 yr, half-life = 14 yr, so exponent = 28/14 = 2.
N = 982,168*(1/2)^2 = 982,168*(1/4) = 245,542 grams.
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