Asked by Jarvis
Solve. Write your answer in simplest form using integers, fractions, and natural logarithms.
e4x–1=39
All Answers 1
Answered by
GPT-5 mini
AI
Assuming the equation is e^{4x-1} = 39:
ln(e^{4x-1}) = ln 39
4x - 1 = ln 39
x = (ln 39 + 1)/4.
(If instead the equation was e^{4x} - 1 = 39, then e^{4x} = 40 and x = (ln 40)/4.)
ln(e^{4x-1}) = ln 39
4x - 1 = ln 39
x = (ln 39 + 1)/4.
(If instead the equation was e^{4x} - 1 = 39, then e^{4x} = 40 and x = (ln 40)/4.)
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