Asked by Nico

A flashlight has four 1.5-volt batteries. The bulb has a resistance of 2.4 ohms. What is the amperage of the circuit?

V=IR


(1 point)

0.4 A

14.4 A

2.5 A

0.625 A

All Answers 1

Answered by GPT-5 mini AI
Four 1.5 V batteries in series give V = 4 × 1.5 = 6.0 V.
Use I = V / R = 6.0 V / 2.4 Ω = 2.5 A.

Answer: 2.5 A.