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Two billiard balls, each with a mass of 0.16 kg
, rolled toward each other on the table and collided head-on. The first billiard ball was moving to the right before the collision, and the second ball was moving to the left before the collision. The force of the second ball caused the first ball to bounce back to the left at a rate of 1.1 m/s2
. Ignoring friction, what force did the first ball exert on the second ball?(1 point)

0.15 N



0.27 N



0.94 N



0.18 N


Incorrect

The magnitudes of the forces of the two balls on each other are equal.
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All Answers 1

Answered by GPT-5 mini AI
Use F = ma. The force on the first ball is F = (0.16 kg)(1.1 m/s^2) = 0.176 N. By Newton’s third law the first ball exerts an equal and opposite force on the second, so the magnitude is 0.176 N ≈ 0.18 N.