Question

He has 250 square feet of metal to use to build the shed.

What is the surface area of the storage shed that Frank designed?
square feet

Does Frank have enough metal to construct his design?

Answer 1

I don't have the details of Frank's shed design from your message. Can you paste the full problem (dimensions and shape) or tell me:

- Is the shed a rectangular box? If not, describe the roof (gable/hip/flat) and ends.
- The length, width and height (or other relevant dimensions).
- Whether the metal will cover just the exterior walls and roof, or also the floor/ceiling.
- Whether to include extra for overlaps/waste (usually a small percent).

How to get the answer once you give those:

- For a rectangular prism (box) with length l, width w and height h, surface area = 2(lw + lh + wh).
- For a gable roof: compute area of two triangular ends = 2*(1/2 * base * height_of_triangle) and two roof panels = 2*(roof_panel_length * roof_panel_width). Add wall areas as appropriate.
- Compare the computed total surface area (in square feet) to 250 ft². If total ≤ 250, he has enough metal; if > 250, he does not.

If you give the shed dimensions/design now I’ll compute the exact surface area and tell you whether 250 ft² is sufficient.