Asked by hey
In which of the following tables does the function have the greatest value when
x
=
10
?
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All Answers 1
Answered by
GPT-5 mini
AI
I can’t see the images. Please either upload the four tables again or type each table’s x and y values here.
If you want to try it yourself, here’s how to get the function value at x = 10 for each table:
1. Look for the pattern in the y-values:
- If the differences between consecutive y’s are constant → linear. Compute slope m = (y2−y1)/(x2−x1), find b from y = mx + b, then evaluate y(10).
- If the ratios between consecutive y’s are constant → exponential. Compute ratio r = y2/y1, then y(10) = y_k * r^(10 − x_k) using any known point (x_k,y_k).
- If second differences are constant → quadratic. Use three points to solve for y = ax^2 + bx + c (or extend the second-difference pattern to x = 10).
- If neither, determine the rule from the table (could be piecewise or another formula) and apply it to x = 10.
2. Example (illustration):
- Table: x = 1,2,3 and y = 3,5,7. Differences are +2 → linear.
m = 2, use point (1,3): 3 = 2(1) + b → b = 1, so y = 2x + 1 → y(10) = 21.
Send the four tables and I’ll compute y(10) for each and tell you which is greatest.
If you want to try it yourself, here’s how to get the function value at x = 10 for each table:
1. Look for the pattern in the y-values:
- If the differences between consecutive y’s are constant → linear. Compute slope m = (y2−y1)/(x2−x1), find b from y = mx + b, then evaluate y(10).
- If the ratios between consecutive y’s are constant → exponential. Compute ratio r = y2/y1, then y(10) = y_k * r^(10 − x_k) using any known point (x_k,y_k).
- If second differences are constant → quadratic. Use three points to solve for y = ax^2 + bx + c (or extend the second-difference pattern to x = 10).
- If neither, determine the rule from the table (could be piecewise or another formula) and apply it to x = 10.
2. Example (illustration):
- Table: x = 1,2,3 and y = 3,5,7. Differences are +2 → linear.
m = 2, use point (1,3): 3 = 2(1) + b → b = 1, so y = 2x + 1 → y(10) = 21.
Send the four tables and I’ll compute y(10) for each and tell you which is greatest.
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