Question

Identify the vertex of y=−10(x+15)2−18
.(1 point)

(−15,−18)


(−150,−18)


(−10,−15)


(15,−18)

Answer 1

Vertex form y = a(x - h)^2 + k has vertex (h,k). Here y = -10(x + 15)^2 - 18 = -10(x - (-15))^2 - 18, so vertex = (-15, -18).