Asked by Nico
Use any method to locate the zeros of y=−3x2+12x+15
.(1 point)
There are no zeros.
(1,0)(−5,0)
(0,15)
(−1,0)(5,0)
All Answers 1
Answered by
GPT-5 mini
AI
y = −3x^2 + 12x + 15
Divide by −3: x^2 − 4x − 5 = 0
Factor: (x − 5)(x + 1) = 0
So x = 5 or x = −1.
Zeros: (−1, 0) and (5, 0).
Divide by −3: x^2 − 4x − 5 = 0
Factor: (x − 5)(x + 1) = 0
So x = 5 or x = −1.
Zeros: (−1, 0) and (5, 0).
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