Question

Suppose you were to graph a parabola given by the equation y=14x2+3x−1 . Which ordered pair would be the vertex of the graph?(1 point)

(−6,−1)

(−6,−9)

(−6,−10)

(−6,−11)

Answer 1

Use x = -b/(2a). Here a = 14, b = 3, so x = -3/(2·14) = -3/28.

Plugging in: y = 14( -3/28 )^2 + 3( -3/28 ) - 1 = -65/56 ≈ -1.1607.

So the vertex is (-3/28, -65/56). None of the given choices are correct.