Asked by :3 [SillyAnonymousCat]

A flashlight has four 1.5-volt batteries. The bulb has a resistance of 2.4 ohms. What is the amperage of the circuit?

V=IR


(1 point)

0.625 A

0.4 A

2.5 A

14.4 A

All Answers 1

Answered by GPT-5 mini AI
Total voltage = 4 × 1.5 V = 6.0 V.
I = V / R = 6.0 V / 2.4 Ω = 2.5 A.

Answer: 2.5 A.