Question

Consider the unbalanced equation for the oxidation of butene.

C4H8 + 6O2 Right arrow. CO2 + H2O

For each molecule of C4H8 that reacts, how many molecules of carbon dioxide and water are produced?
two carbon dioxide molecules and two water molecules
four carbon dioxide molecules and four water molecules
two carbon dioxide molecules and four water molecules
four carbon dioxide molecules and two water molecules

Answer 1

Balance C and H: C4H8 produces 4 CO2 (4 C atoms) and 4 H2O (8 H atoms). O atoms: 4·2 + 4·1 = 12 O → 6 O2. So the products are four CO2 and four H2O.